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	<title>IPCHAMBER &#187; Formula</title>
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		<title>Full mesh formula</title>
		<link>http://ipchamber.kr-cpd.pl/wordpress/?p=199</link>
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		<pubDate>Tue, 11 Oct 2011 11:15:14 +0000</pubDate>
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				<category><![CDATA[Formula]]></category>
		<category><![CDATA[mesh]]></category>

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		<description><![CDATA[How to count how much connections we need to build a full mesh ? x = n*(n-1)/2 x &#8211; number of connections n &#8211; number of devices example for 5 devices: we need: 5*(5-1)/2 = 5*4/2 = 20/2 = 10 &#8230; <a href="http://ipchamber.kr-cpd.pl/wordpress/?p=199">Continue reading <span class="meta-nav">&#8594;</span></a>]]></description>
				<content:encoded><![CDATA[<p style="text-aligin: left;">How to count how much connections we need to build a full mesh ?</span></p>
<h1 style="text-aligin: left; color: #ccffcc;">x = n*(n-1)/2</h1>
<ul>
<li>x &#8211; number of connections</li>
<li>n &#8211; number of devices</li>
</ul>
<p>example for 5 devices: <br />
we need: <br />
<em>5*(5-1)/2 = 5*4/2 = 20/2 = 10</em> <br />
connections to build a full mesh beetween them. </p>
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